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The second option is better. To win you have to bet that the second ball is the same color as the first ball. The second option could have 30 and 30 (worst cas
by corpMaverick 3y ago
The second option is better.
To win you have to bet that the second ball is the same color as the first ball.
The second option could have 30 and 30 (worst case) or it could have 59 and 1(best case), so almost any ball mix is better or equal than the first option when you only have about 50% chances of wining.
- gameman144 3y agoWhy would 30 and 30 be the worst case? You could have drawn a statistically improbable first ball, no? E.g. in your 59:1 example, you could have drawn the 1 rare ball.
- ajmurmann 3y agoOne draw isn't enough to establish a frequency anyways. You want to draw a few times and then pick a strategy. Of course it's important to differentiate with this between worst case urn composition and worst case draws.
- chirau 3y ago30:30 is not the worst case. You could have picked the only ball of a different color. i.e. 1:59. Best case is 60:0 Worst case is 1:59