3 ms·It isn't equivalent to it. See my other comment.by sfpotter 3y agoIt isn't equivalent to it. See my other comment.tipsytoad 3y agoDude. Cos(x, y) = x . y / ||x|| * ||y|| If x and y are normalized: Cos(x, y) = x . ysfpotter 3y agox*y/|x||y| is a very different function from x*y It also isn't a distance...