3 ms·

Dot product is equivalent to cosine similarly for normalized vecotrs

• wongarsu 3y ago
  Given normalized vectors, it's also proportional to the square of the Euclidian distance. Meaning for ranking (and thus k-nearest-neighbors) it doesn't matter if you use Euclidian distance or cosine similarity, you get the same result.
• sfpotter 3y ago
  It isn't equivalent to it. See my other comment.
  • tipsytoad 3y ago
    Dude. Cos(x, y) = x . y / ||x|| * ||y|| If x and y are normalized: Cos(x, y) = x . y
    • sfpotter 3y ago
      x*y/|x||y| is a very different function from x*y It also isn't a distance...