3 ms·
def int2binary(num): lis=[] while True: if num==0 or num==1: lis.append(num) break lis.append(num%2) num
by ATHERALIZAIR 3y ago
def int2binary(num):
lis=[]
while True:
if num==0 or num==1:
lis.append(num)
break
lis.append(num%2)
num=num//2
lis.reverse()
num=''
for i in lis:
num+str(i)
return num
print('Number\t\tBinary Form')
for i in range (100,1001):
print(i,int2binary(i),sep='\t\t')