3 ms·
Thank you! This why the Jordan Form exists at all. (All real symmetric, or more generally Hermitian matrices are diagonalizable, which is the Spectral Theorem.
by FooBarBizBazz 3y ago
Thank you! This why the Jordan Form exists at all.
(All real symmetric, or more generally Hermitian matrices are diagonalizable, which is the Spectral Theorem.)