You still need a way of normalizing expressions that is consistent with your runtime. To say that types ((x: bool) => F<true && x>) and ((x: bool) => F<false ||

You still need a way of normalizing expressions that is consistent with your runtime. To say that types ((x: bool) => F<true && x>) and ((x: bool) => F<false || x>) are the same, wrt judgemental equality, requires normalizing both to ((x: bool) => F<x>).