3 ms·
Maybe it's just what I'm used to, but doing anything other than calculating the value of an expression with RPN seems hard to me. (x-3)(x+2)-8 > 2x^2+3
by ajuc 3y ago
Maybe it's just what I'm used to, but doing anything other than calculating the value of an expression with RPN seems hard to me.
(x-3)(x+2)-8 > 2x^2+3
x^2-x-8 > 2x^2+3
x^2+x+8 < -3
x^2+x+11 < 0
vs
x 3 - x 2 + * 8 - x x * 2 * 3 + >
how would I simplify the expressions here? Maybe it's possible without transforming to infix but I can't do it.