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As far as I understand, Kotlin doesn't actually have first class blocks like Ruby, despite the appearance that it does. Instead, blocks are syntactic sugar for

As far as I understand, Kotlin doesn't actually have first class blocks like Ruby, despite the appearance that it does. Instead, blocks are syntactic sugar for anonymous functions, so y = foo() { bar(it) } is just pretty syntax for y = foo({ it -> bar(it) })

oh_sigh 3y ago
What's the difference?
- nerdponx 3y ago
  Functionally, not that much. But in Ruby it requires a special language construct, whereas in Kotlin it's just pretty syntax for something else that's already in the language.