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> For example, in Bayesian logic: x AND y is xy, x OR y is x + y - xy No it isn't. P(x AND y) = P(x)P(y) only in the special case where x and y are independent
by tr352 3y ago
> For example, in Bayesian logic: x AND y is xy, x OR y is x + y - xy
No it isn't. P(x AND y) = P(x)P(y) only in the special case where x and y are independent. Unlike fuzzy logic, probabilistic logic is not truth functional.
- dragonwriter 3y ago> No it isn’t. P(x AND y) = P(x)P(y) only if x and y are independent. You are obviously correct, and I shouldn’t post when I should be sleeping. > Unlike fuzzy logic, probabilistic logic is not truth functional. Its been a long time since I had much engagement with fuzzy logic, but I distinctly remember it being constructed as a class such that Bayesian probability was a fuzzy logic, though the others of interest were much simpler. But that may be as wrong as the other part of that post...