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I think the term of interest here is non-computable: irrational numbers can have finite kolmogorov complexity. You're kind of "begging the question" here, wher
by kmod 3y ago
I think the term of interest here is non-computable: irrational numbers can have finite kolmogorov complexity.
You're kind of "begging the question" here, where you're assuming that non-computable numbers exist and then using that to show that some numbers are non-computable. You can definitely show that these things exist, but that relies on "believing" the set of axioms that you used to prove it.
- rbanffy 3y agoHow do we identify a specific non-computable number?