If it's still using IBM code, then it definitely will. IBM's OS/2 kernel, even the 32-bit one from 2.0 onwards, had 16-bit code and the extra ring usage for IO

If it's still using IBM code, then it definitely will. IBM's OS/2 kernel, even the 32-bit one from 2.0 onwards, had 16-bit code and the extra ring usage for IOPL. Then there's the fact that the rest of it is 32-bit. (-: