Yes, play of words. And with a choosen weight function. If, e.g., the weight function would not be ‘sum over all distances in a given timeframe with the same w

Yes, play of words. And with a choosen weight function. If, e.g., the weight function would not be ‘sum over all distances in a given timeframe with the same weight’ but for instance ‘… with weight 1/(distance^2), the results would be different (mercury would not win for each planet). I guess if someone asks, ‘which neighbour’ is closest, I would say the neighbour living literally next door, even though on workdays our distance is much larger (as we work in different cities) then that other neighbour three blocks down who works in the same city as myself.