4 ms·
In more formal terms, since it is a uniform distribution you can write random(x) = random()*x then you can easily see that random(random(random())) = ran
by awegio 3y ago
In more formal terms, since it is a uniform distribution you can write
random(x) = random()*x
then you can easily see that
random(random(random())) = random()*random()*random()
The resulting distribution is not equal to random()^3, because e.g. the probability that all 3 random calls give you a number <0.5 is only 0.125.
- jwsteigerwalt 3y agoClear and simple explanation
- hedora 3y agoOh. Thanks for the explanation, but I thought random was taking a seed, which would have made this much cooler, like this: https://www.jstatsoft.org/article/download/v007i03/892 https://www.jstatsoft.org/article/download/v007i03/892
- ibrahimbeladi 3y agoIt depends on the language, some languages like JS does not take an argument. So, it is language-specific.
- IIAOPSW 3y agoTook me a moment to understand that by random()^3 you meant the output of the random function to the power of 3, not some temporary function which we name "random^3" since that's also how we build it.