3 ms·
Where 1 <= x <= 4: f(x) = (x-1)/9 + 1, maps bijectively from [1,4] to [1,4/3] g(x) = (x-1)/9 + 4/3, maps bijectively from [1,4] to [4/3,5/3] h(x) = (x-1)/9 +
by drt1245 15y ago
Where 1 <= x <= 4:
f(x) = (x-1)/9 + 1, maps bijectively from [1,4] to [1,4/3]
g(x) = (x-1)/9 + 4/3, maps bijectively from [1,4] to [4/3,5/3]
h(x) = (x-1)/9 + 5/3 maps bijectively from [1,4] to [5/3,2]
Therefore, [1,2] must contain three times as many numbers as [1,4], right?
It doesn't work like that.
- powertower 15y agoI'm not sure what you are doing with the above.