2 ms·
the problem is the second interpretation is wrong. for example, exp(x) would give a higher value than it does since the average value of the exponent of a range
by adgjlsfhk1 3y ago
the problem is the second interpretation is wrong. for example, exp(x) would give a higher value than it does since the average value of the exponent of a range is higher than the exponent of it's center.
- regularfry 3y agoYep. For a sequence of operations to work on a range you do actually need to track both ends of the range, not just one of them. Otherwise what you end up implicitly doing is flipping lossily between a range interpretation and a point interpretation and back again.