3 ms·

Is `dy/dx` ever distinct from `d/dx y`? Generally I've treated `df(x)/dx` as just another way to write the operator `d/dx` applied to `f(x)`, which I don't thin

Is `dy/dx` ever distinct from `d/dx y`? Generally I've treated `df(x)/dx` as just another way to write the operator `d/dx` applied to `f(x)`, which I don't think of as a fraction.

lupire 3y ago
dy/dt = dy/dx * dx/dt
- xvedejas 3y ago
  That's just the chain rule, right? d/dt y(t) = ( d/dx y(x) )( d/dt x(t) )