3 ms·
> That is ℝ[X]/≺X²≻. > Another way of thinking of this is to have an element ℇ different from zero, such that ℇ ²= 0 and hand wave the fact that the dual part
by JadeNB 3y ago
> That is ℝ[X]/≺X²≻.
> Another way of thinking of this is to have an element ℇ different from zero, such that ℇ ²= 0 and hand wave the fact that the dual part of the number carry the derivative.
Aren't these the same way of thinking?
- lupire 3y agoDifferent way of thinking about same thing. A more common example of this idea is √(-1): R[x]/<x²+1> vs i²+1=0.