4 ms·
No, it wouldn’t count: “work” in this context is a technical physics term meaning a force applied over a distance.
by zopa 3y ago
No, it wouldn’t count: “work” in this context is a technical physics term meaning a force applied over a distance.
- c22 3y agoIf you are not observing some force over some distance then what, exactly, are you observing?
- xboxnolifes 3y agoConstant motion doesn't require constant force.
- fsckboy 3y agoobservation requires the transmission of information to the observer, how is it being proposed to do this without force? The question on the table is "constructing a toy which demonstrates" and demonstration requires observation, I think is what is being said
- frutiger 3y agoFor example, perfectly circular motion against no resistance requires no work since the force is always perpendicular to the motion.
- fsckboy 3y agohe's saying you can't observe the phenomenon you are talking about without some additional work being done, which you might say is not part of the system, but it is part of the system that G*P proposed