4 ms·
You can get away with remembering less than the article suggests. Logs of 0 and 10 are easy. Then, if you have the logs of 2, 3 and 7, you can easily calculate
by nemoniac 3y ago
You can get away with remembering less than the article suggests.
Logs of 0 and 10 are easy. Then, if you have the logs of 2, 3 and 7, you can easily calculate the logs of 4, 5, 8 and 9. From there you can go a long way by factorization and approximation.
- madcaptenor 3y agoYou can do a lot with just two facts: - log 2 ~ 3/10 (which should be familiar to this audience) - log 3 ~ (19/12) log 2 ~ 19/40 (in musical terms this is the fact that seven semitones make a perfect fifth) - although arguably you don't even need this, since you can derive the same approximation by noting that log 8 ~ 9/10 and interpolating between log 8 and log 10.