3 ms·
Bitwise multiplication is bitwise ‘and’, so exponentiation (repeated multiplication) is the identity, so aⁿ+bⁿ=cⁿ iff a+b=c. I have a truly remarkable proof of
by kps 4y ago
Bitwise multiplication is bitwise ‘and’, so exponentiation (repeated multiplication) is the identity, so aⁿ+bⁿ=cⁿ iff a+b=c. I have a truly remarkable proof of this, but my filesystem is full.