4 ms·
At these rotation speeds (10h33m/45m) how much of the planets diameter is due to rotation forces pushing the matter outwards. I guess the solution would requir
by throwaway_ab 3y ago
At these rotation speeds (10h33m/45m) how much of the planets diameter is due to rotation forces pushing the matter outwards.
I guess the solution would require a comparison to a hypothetical Saturn that has no rotation. If that's even possible.
- JumpCrisscross 3y ago> the solution would require a comparison to a hypothetical Saturn that has no rotation. If that's even possible. Possible. But not probable. For one, you’d need a complete cancellation of angular momentum during formation, which is unlikely. Also, without a dynamo, even at that distance from the sun, the lighter gases would wash away.
- kijin 3y agoSaturn's equatorial radius is 60,268km, and its polar radius is 54,364km -- nearly 10% smaller. The equatorial radius would have been smaller without the rapid rotation, and the polar radius larger, so at least we have lower and upper limits as to the size of a non-rotating Saturn. Getting a more accurate estimate would require calculating the effect of gravity vs. centrifugal force on the density of the various gaseous layers. As long as you limit the calculation to the current state of Saturn (as if it had just stopped) and not try to extrapolate over its entire age of 4.6B years, the result is unlikely to be more than a couple of percentage points different from the current average radius.