4 ms·
I^n is just a countably infinite subset of R^n.
by yarg 3y ago
I^n is just a countably infinite subset of R^n.
- Skeime 3y agoNo, I^n is also uncountable. In fact, the usual proof for the uncountability of R is really proof of the uncountability of I, and then the natural injection into R is used to extend it to R.