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I find the terminology that Haskell uses quite misleading for software engineering. It borrows concepts from category theory with quaint names such as a "monad"
by Hirrolot 4y ago
I find the terminology that Haskell uses quite misleading for software engineering. It borrows concepts from category theory with quaint names such as a "monad", "endofunctor", "catamorphism", etc. The problem is that, instead of a "monad", we can say "brrrdogcogfog" and nothing will change -- the name is absolutely irrelevant to the problem being solved. Given that a monad is an interface for sequential computation, a much better name would be something like "Seq", "SeqComp", or something like that.
- medstrom 4y agoLike a Javascript ArrayBuffer? No, a Stream?
- viscanti 4y agoA monad is just a monoid in the category of endofunctors. Would most people know what "brrrdogcogfog" means? Couldn't we make that argument about literally any word? I don't see why it applies more here than elsewhere. For people who have experienced it before, it's straightforward and easy to work with, for those who haven't, then there's a learning curve. No one would likely have encountered "brrrdogcogfog" before and everyone would have to go through the learning curve.
- throwaway17_17 4y agotl;dr -> I agree that the terminology is probably not something that enhances cohesion amongst devs using Haskell, and certainly can be distracting in a pedagogical setting. I think the fact your experience leads you to believe that a monad is an interface for sequential computation. A monad is often used for ordering computations, but Haskell’s monads can also be commutative (like the Reader instance of monad) which do not order anything. The real issue is that the naming convention where some typeclass is named after a concept in category theory means wildly different things to different developers. For instance, I would expect a type/typeclass named for some categorical construct to behave in the way the categorical construct behaves and that would be the extent of what I use it for. However, some developer may see a particular usage the same construct and extrapolate that said construct is intrinsically tied to that algorithmic pattern of usage. So the problem is controlling expectation and managing consistency throughout the dev community. I doubt Haskell will ever get away from the category theory inspired libraries and the subsequent naming conventions. See the relatively lively development of the profunctor optics based work. But, I can certainly see how it may distract or confuse newcomers.
- pharmakom 4y agoF# calls them Computation Expressions which is far more approachable imo
- nequo 4y agoThat sounds almost as vague to me as “object” does in OOP. Don’t non-monadic functions also consist of expressions that describe computations?
- pharmakom 4y agoEverything is vague. Hell, Haskell functions are not really functions in the mathematical sense.
- nequo 4y agoTo me, “computation expression” is significantly more vague than “function” is in Haskell. “Seq” as was suggested by someone else here seems clearer. But I would genuinely be happy to understand the F# point of view on this better.
- truculent 4y agoAs I understand it, monads help solve the problem of sequential computation in Haskell but the concept is not limited to that. For example, how would you consider the monadic properties of data type like Maybe or Either to be (exclusively?) interpreted through the lens of sequential computation? What about commutative monads where the order doesn’t matter?
- solomonb 4y agoThe `Monad` instance for `Maybe` and `Either` is precisely for doing sequential computation! Consider the following: myBigSubroutine :: Maybe Int -> Maybe Int -> Maybe Bool myBigSubroutine ma mb = do a <- ma b <- mb return (a > b) Here we are sequencing the "effect" of optionality. `ma` must be evaluated before `mb` and if it returns a `Nothing` then we short circuit and do not evaluate `mb`.
- truculent 4y ago> `ma` must be evaluated before `mb` No - either one can be evaluated first, with the other being short-circuited. If you swap the order of those lines, the function is exactly the same (in terms of inputs and outputs, at least).
- solomonb 4y agoThis `do` syntax desugars to binds like: ma >>= \a -> mb >>= \b -> return (a > b) We can then inline the definition of `>>=` and `return` to get: case ma of Nothing -> Nothing Just a -> case mb of Nothing -> Nothing Just b -> Just (a > b) Imagine that `mb` is actually a really expensive computation that we don't want to perform unless `ma` returns a value. Sequencing our case statements in this way allows us to do that. `mb` will remain an unevaluated thunk until `ma` evaluates to a `Just a` value.
- gemstones 4y agoI think the commenter who mentioned syntax is on to something. If I write this fn my_big_subroutine(ma: Option<isize>, mb: Option<isize>) -> Option<bool> { match (ma, mb) { (Some(a), Some(b)) => Some(a > b), (_, _) => None, } } it’s clearer to me what the intent is. I’m not sure why the other syntax is so hard for me but it feels hard to understand for some reason.
- matheusmoreira 4y ago> Given that a monad is an interface for sequential computation And what the hell is an interface for sequential computation? I think I understand what these Maybe types are and what they accomplish but "interface for sequential computation" sounds a lot like those buzzwords people mix together that could mean anything.
- hgsgm 4y agoIt's an API for ensuring work gets done in a specified order. Like opening the jar before sticking a knife into the peanut butter.
- matheusmoreira 4y agoYeah, well, so is every programming language ever created. When I write any code at all, it's to ensure the instructions are laid out in the correct order for the computer to execute.
- consilient 4y ago> Given that a monad is an interface for sequential computation, a much better name would be something like "Seq", "SeqComp", or something like that. Just because you can look at something as describing a computation doesn't mean you always should. For example: data BinaryTree x = | Leaf x | Node (BinaryTree x) (BinaryTree x) instance Monad BinaryTree where return :: a -> BinaryTree a return x = Leaf x bind :: (a -> BinaryTree b) -> BinaryTree a -> BinaryTree b bind f (Leaf x) = f x // replace a leaf with the result of calling f on its label bind f (Node l r) = Node (bind f l) (bind f r) // traverse down the tree, ultimately replacing all the leaf nodes with a new subtree You can choose to interpret a binary tree as describing nondeterministic computation where you have two choices at every step, but I rarely do. Most of the time trees are just trees.
- hgsgm 4y agoThe tree is a tree, but the Monad instance is sequencing modifications to the tree.
- consilient 4y agoSure, Kleisli arrows `a -> m b` are generally best interpreted in a computational sense. But with something like `IO`, the actual objects `m b` are computations as well, and this intuition is not as broadly applicable.
- keithalewis 4y agoComposition/SeqComp comes for free. A monad is how to wrap something up,apply a function to the wrapped up thing, and how to unwrap it.
- hgsgm 4y agoComposition is not sequential in a pure, lazy language with a graph reduction runtime like Haskell.