4 ms·
When you do `*(pointer + 1)`, it'll actually increment the address of the pointer by `sizeof(*pointer)`, so it indeed works the same as indexing `pointer[1]`
by FreeFull 4y ago
When you do `*(pointer + 1)`, it'll actually increment the address of the pointer by `sizeof(*pointer)`, so it indeed works the same as indexing `pointer[1]`