The (presumably relative) error of 0.05% implies only ~11 significant bits, while 32-bit and 64-bit floating point formats have 24 and 53 significant bits respe

The (presumably relative) error of 0.05% implies only ~11 significant bits, while 32-bit and 64-bit floating point formats have 24 and 53 significant bits respectively. If your sine has only 11 correct bits and you are okay with that, why do you have much more than 11 bits of input precision after all? EDIT: Someone (sorry, the comment was removed before I could cite one) mentioned that it is actually for Q1.15 fixed point. So it was not even an "alternative" implementation...