In the syntax `a < b < c` both the `<` are different operators than the `<` in `a < b`. It is more similar to the ternary operator `a ? b : c`. It could also j

In the syntax `a < b < c` both the `<` are different operators than the `<` in `a < b`. It is more similar to the ternary operator `a ? b : c`. It could also just be a type error: `<` takes two integers and produces a boolean, so both `(a < b) < c` and `a < (b < c)` would be invalid.