4 ms·
This is conditional on there being 2 simultaneous orders, right? If there's a single pickup per restaurant at any given time, the odds are 0, not .02%.
by justrealist 4y ago
This is conditional on there being 2 simultaneous orders, right? If there's a single pickup per restaurant at any given time, the odds are 0, not .02%.
- orlp 4y agoYes, but conversely if there's 10 simultaneous orders the probability is 1 - (4095/4096) * (4094/4096) * ... * (4087/4096) = 1.093% to have a collision with a code consisting of 3 hexadecimal characters.