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That’s not right. For example, if you have access to any sort of radical you still can’t solve the quintic.
by onos 4y ago
That’s not right. For example, if you have access to any sort of radical you still can’t solve the quintic.
- iamerroragent 4y ago"Without it, one needs to resort to iterative root-finding, which works for polynomials of any order." I believe that's what they mean for quintics. It's been a while for me apologies if I'm miss remembering here.
- geysersam 4y agoBut if you have access to an extended set of operations (ultraradicals), in particular an operation that solves a parameterized quintic, you can solve all quintics. https://en.m.wikipedia.org/wiki/Bring_radical https://en.m.wikipedia.org/wiki/Bring_radical
- openasocket 4y agoI believe that doesn't extend beyond degree 6 polynomials though. Isn't that Hilbert's 13th problem?
- chongli 4y agoJust use Newton's method!
- justeleblanc 4y agoI can't tell if this is a joke. Newton's method will give you an approximate answer.
- chongli 4y agoYou can write the answer as a recurrence in symbolic form.
- hsjqllzlfkf 4y ago[dead]
- onos 4y agoOr better yet, gpt