Sorry my mistake, I was talking without looking at the datasheet. From the datasheet >all quiescent operating current is returned to the output terminal. This

Sorry my mistake, I was talking without looking at the datasheet. From the datasheet >all quiescent operating current is returned to the output terminal. This imposes the requirement for a minimum load current. If the load current is less than this minimum, the output voltage will rise. I've used an LM317 drawing less than 2mA, so I assumed it was possible (in hindsight I must have used the solution, below). The solution is very simple however, make a separate parallel circuit that will draw at least 2mA. This can be accomplished just by placing a resistor of appropriate value between the Vout and ground.