3 ms·
Regarding conflicting ranges— In a[i:j:k], 0 <= i, i <= j, j <= k, and k <= cap(a). If not, then the operation will panic.
by klodolph 4y ago
Regarding conflicting ranges—
In a[i:j:k], 0 <= i, i <= j, j <= k, and k <= cap(a). If not, then the operation will panic.