3 ms·

every argument is passed by move, not just almost every. Types that implement Copy are still moved. Copy just means “the original value is still usable after m

• cmrdporcupine 4y ago
  fair enough, but also the semantics of a Rust 'move' aren't identical to C++ std::move anyways. you can "get it back" after the function call, as it's a borrow, not a move. Makes me wonder out loud if the C++ community isn't going to add some kind of std::borrow/std::return_borrowed to the language. If that's even feasible with the type system and reference system as it is today.