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The most immediately interesting result to me here is the significant variability between states, with Florida having roughly twice the national rate. Obviousl

The most immediately interesting result to me here is the significant variability between states, with Florida having roughly twice the national rate. Obviously comparing Florida to Idaho isn't apples to apples, but Florida has similar population density and population as New York and more than 3 times as many pedestrian deaths per capita. Obviously how roads and cities are designed must be a factor, as well as presumably other state-by-state variables.

rootusrootus 4y ago
> other state-by-state variables Like weather, judging from how there is a pretty clear north-south gradient.
- bobthepanda 4y ago
  Weather is probably indirect. The south urbanized and suburbanized later due to the invention and adoption of air conditioning, which was around the same timeframe as our movement towards cars.
- deleted 4y ago
  [deleted]
ars 4y ago
Florida has significantly older drivers. That probably explains all of the difference.
tzs 4y ago
> Florida has similar population density and population as New York and more than 3 times as many pedestrian deaths per capita. The two states have similar density (FL 406/mi^2, NY 412/mi^2), but what is probably more relevant is the average "experienced density". What I mean by "experienced density" is the average over all residents of the densities of their cities. New York City has a density of 27500/mi^2, and 42% of New York residents are in NYC, so even if we play it safe and assume everyone outside of NYC lives in a place with 0 density, the average experienced density in New York would be 11550/mi^2. Florida only has one city approaching NYC density, Sweetwater (25600/mi^2), and that only has 20500 people. The next four densest range from 12800-11860/mi^2, and have populations of 38700, 1000, 21500, and 53410. Its most populous city, Jacksonville at 838000 has a density of only 960/mi^2. Taking all 919 Florida cities that have density data at usa.com [1] I get an average experienced density for their residents of 3096/mi^2. Those cities account for about 68% of the population. If we make the very generous assumption that the remaining 32% live somewhere as dense as the second densest Florida city, we'd get an average experienced density of 6200/mi^2 for the state, just over half that of New York. If we make the more realistic assumption that the remaining 32% live in places with densities around the state average of 406/mi^2, we get an average experienced density in Florida of 2240/mi^2, less than 20% that of New York. [1] http://www.usa.com/rank/florida-state--population-density--city-rank.htm http://www.usa.com/rank/florida-state--population-density--c...

rootusrootus 4y ago

> other state-by-state variables Like weather, judging from how there is a pretty clear north-south gradient.

bobthepanda 4y ago
Weather is probably indirect. The south urbanized and suburbanized later due to the invention and adoption of air conditioning, which was around the same timeframe as our movement towards cars.
deleted 4y ago
[deleted]

ars 4y ago

Florida has significantly older drivers. That probably explains all of the difference.

tzs 4y ago

> Florida has similar population density and population as New York and more than 3 times as many pedestrian deaths per capita. The two states have similar density (FL 406/mi^2, NY 412/mi^2), but what is probably more relevant is the average "experienced density". What I mean by "experienced density" is the average over all residents of the densities of their cities. New York City has a density of 27500/mi^2, and 42% of New York residents are in NYC, so even if we play it safe and assume everyone outside of NYC lives in a place with 0 density, the average experienced density in New York would be 11550/mi^2. Florida only has one city approaching NYC density, Sweetwater (25600/mi^2), and that only has 20500 people. The next four densest range from 12800-11860/mi^2, and have populations of 38700, 1000, 21500, and 53410. Its most populous city, Jacksonville at 838000 has a density of only 960/mi^2. Taking all 919 Florida cities that have density data at usa.com [1] I get an average experienced density for their residents of 3096/mi^2. Those cities account for about 68% of the population. If we make the very generous assumption that the remaining 32% live somewhere as dense as the second densest Florida city, we'd get an average experienced density of 6200/mi^2 for the state, just over half that of New York. If we make the more realistic assumption that the remaining 32% live in places with densities around the state average of 406/mi^2, we get an average experienced density in Florida of 2240/mi^2, less than 20% that of New York. [1] http://www.usa.com/rank/florida-state--population-density--city-rank.htm http://www.usa.com/rank/florida-state--population-density--c...