2 ms·He has set, not functional. See his Twitterby rurban 4y agoHe has set, not functional. See his Twitterbslatkin 4y agoIt's SSA. If you use (define) in Racket is it no longer functional?rurban 4y agoIf the setter is at compile-time it might still be functional. If it's at run-time, not. A run-time setter must be a binding (as in lambda args), not an assignment.