3 ms·
Well, there are variable length integers involved, since it's as part of a way of representing variable length integers. But it seems you're right that x is jus
by vintermann 4y ago
Well, there are variable length integers involved, since it's as part of a way of representing variable length integers. But it seems you're right that x is just a regular machine int in this context, as an implementation detail. I misunderstood.