3 ms·
Which the M1/M2 is doing as well... It's just soldered RAM, not on-die RAM. Completely off-the-shelf LPDDR modules that are shipping in dozens of other laptops.
by kllrnohj 4y ago
Which the M1/M2 is doing as well... It's just soldered RAM, not on-die RAM. Completely off-the-shelf LPDDR modules that are shipping in dozens of other laptops. Absolutely nothing special about the RAM at all.
- titzer 4y agoDescribing it as "soldered" is not right. It's on the same package. https://en.wikipedia.org/wiki/Apple_M1 https://en.wikipedia.org/wiki/Apple_M1. There's no multi-centimeter hundred-plus-line bus to drive charges through. Pushing signals through those big long wires takes juice.
- kllrnohj 4y ago> It's on the same package. Which means it's still over an external interconnect, which is what actually "takes juice" > Pushing signals through those big long wires takes juice. lol no it doesn't. That's a pretty minuscule amount of resistance.
- titzer 4y agoResistance is directly proportional to length. Yeah it saves a lot to move the RAM closer by putting it on package. Not sure why you are still trying to argue about basic EE.
- kllrnohj 4y agoMath it out then. How much resistance is that few centimeters of PCB trace costing & what does that translate to in terms of milliwatts? Resistance is proportional to length, yes, but that doesn't make it significant in the given application.