> Of course that makes it possible. Note that it doesn’t say that f is simply measurable. Irrelevant. Again, once again, over again, yet again, for real value

> Of course that makes it possible. Note that it doesn’t say that f is simply measurable. Irrelevant. Again, once again, over again, yet again, for real valued random variable Y, E[Y^2] always exists. > By definition being integrable means E[|f|] < infinity. Wrong. Correcting you is a waste of my time.