3 ms·

Because that's not how the pipe operator works in any other language.

• askonomm 4y ago
  In Clojure it does: (-> "Hello, World" string/uppercase (string/split #",") first string/trim) `->` is a threading-first macro, and `->>` is a threading last macro. More here: https://clojure.org/guides/threading_macros https://clojure.org/guides/threading_macros
  • eyelidlessness 4y ago
    Beat me to it while I was typing! Alas, I’m on mobile and your example is a better illustration of the point.
• eyelidlessness 4y ago
  Of course it is, at least conceptually. See various lisps’ threading macros (which are of course functions over code; but they correspond exactly to mapping over a series of functions, each one supplying input to the next).
  • ezekg 4y ago
    I totally agree, I shouldn't have been so absolute in my statement. But JS is not a lisp. The |> foo bar baz syntax doesn't jive with any other syntax in JS, but foo |> bar |> baz does.
• capableweb 4y ago
  As someone else, it does in Clojure (which is what I wrote most of the time). But even if it didnt, does it matter? If there is a better way, the way is better, no matter if it exists in other languages or not. If all languages tried to be the same, most of them would be boring.