4 ms·
suprised there are three answers that dont mention area. the larger a die is the more expensive it is to produce, since the chance of getting a defect goes up.
by convolvatron 4y ago
suprised there are three answers that dont mention area. the larger a die is the more expensive it is to produce, since the chance of getting a defect goes up. wafer-scale integration works by providing sufficient redundancy and/or routing to avoid damaged areas, but that too has a cost.