Thanks. So, if I read this correctly, barring the simple cases that Zig can detect at compile-time, this means that whether it's a UB (in the C++ definition of

Thanks. So, if I read this correctly, barring the simple cases that Zig can detect at compile-time, this means that whether it's a UB (in the C++ definition of the term) depends on the flags specified by the author of the library and the person who compiles the final binary. That's definitely much better than C++ UB. Still a bit scary, though.