3 ms·

you appear to have failed to understand the question that the questioner was asking.

by platz 4y ago

photochemsyn 4y ago
There are three models in the second link describing the possible mechanisms, none of them seem all that condensable. E.g. this seems to be at the center of one of their approaches: > "If we only consider second-order perturbations, involving two atomic sites in addition to O, the interaction cannot be geometrically chiral. So, if the fount is completely isotropic, we need to consider third-order perturbations, involving three distinct atomic sites, in addition to O, to have the possibility of a chiral coupling. Furthermore, it is apparent that the strength of the perturbations associated with each site is proportional to the scalar charges Q, and a third-order perturbation to the mutation rate will be simply proportional to the product of these charges, which is unchanged on inversion. It is only their relative locations that matter." > "There are several types of third-order perturbation. For example, we can use the first-order displacement due to the first charge to evaluate the electric field due to the second charge along the perturbed trajectory and compute a second-order velocity perturbation to calculate the third-order magnetic displacement at O. Alternatively, we can take the second-order displacement at O and combine this with the electric field due to a third charge to calculate a third-order change in the kinetic energy of the cosmic ray at O. We must then sum over all permutations of charge..." See also Fig B3: > "Figure B3. Example of electric chirality (barber pole model). The electric charge distribution of two biopolymers of opposite chirality projected onto a cylinder is shown, together with the unperturbed vs. perturbed trajectory of a magnetically polarized cosmic ray interacting with the molecule."
- platz 4y ago
  You know, sometimes it's okay to just say that you don't know.
  - photochemsyn 4y ago
    The point of responding to internet questions is to teach yourself something new, not to impress others by flexing your knowledge. Also, one of the best ways to gain new knowledge is to throw something up on the internet and wait for others to explain why you're wrong. I'm rather disappointed in your response, mostly for the latter reason. (I think the perturbation business implies some kind of Feynman diagram, perhaps?)

you appear to have failed to understand the question that the questioner was asking.

by platz 4y ago

you appear to have failed to understand the question that the questioner was asking.

There are three models in the second link describing the possible mechanisms, none of them seem all that condensable. E.g. this seems to be at the center of one of their approaches: > "If we only consider second-order perturbations, involving two atomic sites in addition to O, the interaction cannot be geometrically chiral. So, if the fount is completely isotropic, we need to consider third-order perturbations, involving three distinct atomic sites, in addition to O, to have the possibility of a chiral coupling. Furthermore, it is apparent that the strength of the perturbations associated with each site is proportional to the scalar charges Q, and a third-order perturbation to the mutation rate will be simply proportional to the product of these charges, which is unchanged on inversion. It is only their relative locations that matter." > "There are several types of third-order perturbation. For example, we can use the first-order displacement due to the first charge to evaluate the electric field due to the second charge along the perturbed trajectory and compute a second-order velocity perturbation to calculate the third-order magnetic displacement at O. Alternatively, we can take the second-order displacement at O and combine this with the electric field due to a third charge to calculate a third-order change in the kinetic energy of the cosmic ray at O. We must then sum over all permutations of charge..." See also Fig B3: > "Figure B3. Example of electric chirality (barber pole model). The electric charge distribution of two biopolymers of opposite chirality projected onto a cylinder is shown, together with the unperturbed vs. perturbed trajectory of a magnetically polarized cosmic ray interacting with the molecule."

platz 4y ago
You know, sometimes it's okay to just say that you don't know.
- photochemsyn 4y ago
  The point of responding to internet questions is to teach yourself something new, not to impress others by flexing your knowledge. Also, one of the best ways to gain new knowledge is to throw something up on the internet and wait for others to explain why you're wrong. I'm rather disappointed in your response, mostly for the latter reason. (I think the perturbation business implies some kind of Feynman diagram, perhaps?)