3 ms·
You can start a REPL with `isympy -I`, which is an IPython REPL but with some preprocessing magic that wraps any unknown variable into a sympy symbol and any in
by rav 4y ago
You can start a REPL with `isympy -I`, which is an IPython REPL but with some preprocessing magic that wraps any unknown variable into a sympy symbol and any integer into a sympy integer, which makes it closer to Mathematica:
In [1]: 22/7*foobar
Out[1]:
22⋅fo̅o
──────
7
- anigbrowl 4y agoUnderrated suggestion - thanks a lot.
- schoen 4y agoThis is totally great. In [1]: (foo + 1) ** 7 Out[1]: 7 (foo + 1) In [2]: expand(_) Out[2]: 7 6 5 4 3 2 foo + 7⋅foo + 21⋅foo + 35⋅foo + 35⋅foo + 21⋅foo + 7⋅foo + 1 In [3]: diff(_) Out[3]: 6 5 4 3 2 7⋅foo + 42⋅foo + 105⋅foo + 140⋅foo + 105⋅foo + 42⋅foo + 7 In [4]: expand((cats+dogs)**5) Out[4]: 5 4 3 2 2 3 4 5 cats + 5⋅cats ⋅dogs + 10⋅cats ⋅dogs + 10⋅cats ⋅dogs + 5⋅cats⋅dogs + dogs In [5]: hip + hip + hooray Out[5]: 2⋅hip + hooray