3 ms·
Sure, the insight/intuition comes from diagonalization, or perhaps more directly from Cantor's theorem. For any complexity class O(F(N)), there must exist a co
by Kranar 4y ago
Sure, the insight/intuition comes from diagonalization, or perhaps more directly from Cantor's theorem.
For any complexity class O(F(N)), there must exist a complexity class O(2^F(N)) that is strictly a superset of O(F(N)). If F(N) is decidable then so too is 2^F(N).
https://en.wikipedia.org/wiki/Cantor%27s_theorem https://en.wikipedia.org/wiki/Cantor%27s_theorem