3 ms·
"Some non-zero multiple of sizeof(double)", surely?
by wizofaus 4y ago
"Some non-zero multiple of sizeof(double)", surely?
- mananaysiempre 4y agos/non-zero // double x[1], *p; p = x + 1; /* legal though *p wouldn’t be */
- wizofaus 4y agoSurely in that case x[0] is the object "behind" the pointer (assuming adding 1 puts you ahead!). But using the orginally intended meaning of "behind" here, logically there is no object at all...