3 ms·

Your reasoning is wrong. When at rest the momentum of both balls is zero and when you pull one ball away from the other the change in momentum (and hence the fo

Your reasoning is wrong. When at rest the momentum of both balls is zero and when you pull one ball away from the other the change in momentum (and hence the force) is opposite to the other ball. Thus there is no collision and transfer of energy i.e. each is independent. It is only at the point of collision that the impulsive force is imparted to the other body. See this Khan Academy video "Impulse and momentum dodgeball example" for detailed understanding: https://www.khanacademy.org/science/physics/linear-momentum/momentum-tutorial/v/impulse-and-momentum-dodgeball-example https://www.khanacademy.org/science/physics/linear-momentum/... Also see article "Momentum Change and Impulse Connection" (note the Rebounding Collison section at the bottom) : https://www.physicsclassroom.com/class/momentum/Lesson-1/Momentum-and-Impulse-Connection https://www.physicsclassroom.com/class/momentum/Lesson-1/Mom...

yorwba 4y ago
> when you pull one ball away from the other the change in momentum (and hence the force) is opposite to the other ball. Thus there is no collision and transfer of energy i.e. each is independent Indeed, that was my point. Because "reversing of direction evaluates the numerator as (mv - (-mu)) = mv+mu along with the denominator t being made as small as possible thus resulting in a larger force" is incorrect for the same reason.
- rramadass 4y ago
  No, you still have not understood it; what i am pointing out is a change in momentum after a collision resulting in the Impulsive Force. See the Khan Academy video i linked for a detailed example with numerical calculations; It walks you through the steps involved. Also from my 2nd linked article; Observe that each of the collisions above involve the rebound of a ball off a wall. Observe that the greater the rebound effect, the greater the acceleration, momentum change, and impulse. A rebound is a special type of collision involving a direction change in addition to a speed change. The result of the direction change is a large velocity change.

yorwba 4y ago

> when you pull one ball away from the other the change in momentum (and hence the force) is opposite to the other ball. Thus there is no collision and transfer of energy i.e. each is independent Indeed, that was my point. Because "reversing of direction evaluates the numerator as (mv - (-mu)) = mv+mu along with the denominator t being made as small as possible thus resulting in a larger force" is incorrect for the same reason.

rramadass 4y ago
No, you still have not understood it; what i am pointing out is a change in momentum after a collision resulting in the Impulsive Force. See the Khan Academy video i linked for a detailed example with numerical calculations; It walks you through the steps involved. Also from my 2nd linked article; Observe that each of the collisions above involve the rebound of a ball off a wall. Observe that the greater the rebound effect, the greater the acceleration, momentum change, and impulse. A rebound is a special type of collision involving a direction change in addition to a speed change. The result of the direction change is a large velocity change.