> Java isn't generic over exceptions. You can't write a method that takes an instance of Foo and says "my method throws whatever Foo.bar() throws" If you bend

> Java isn't generic over exceptions. You can't write a method that takes an instance of Foo and says "my method throws whatever Foo.bar() throws" If you bend over far enough backwards, and squint a bit, you can kind of do that... interface Runner<E extends Throwable> { public void run() throws E; } class Test { public static <E extends Throwable, T extends Runner<E>> void test(T runner) throws E { runner.run(); } } It compiles. I haven't tried running it though.