> you don't even have strict order of evaluation You do, with `seq`. And a lot of Haskell programming in practice is deciding between lazy vs strict programmin

> you don't even have strict order of evaluation You do, with `seq`. And a lot of Haskell programming in practice is deciding between lazy vs strict programming. The only lazy feature commonly used by Rust programmers are iterators, but they are just lazy lists (that are immediately discarded after being forced)