5 ms·
Nobody expects subtraction to be closed on the naturals, nor division on the integers. Why would be expect multiplication defined to be closed over fixed-width
by naniwaduni 4y ago
Nobody expects subtraction to be closed on the naturals, nor division on the integers. Why would be expect multiplication defined to be closed over fixed-width integers to coincide with the general arithmetic operation?
- Koshkin 4y agoWell, by your definition even division of reals is not closed - which means that your definition is not a correct one. A closed operation is allowed to have an "undefined" result. (And, by the way, division of integers is perfectly closed, if you ignore the remainder.)
- deleted 4y ago[deleted]
- naniwaduni 4y agoDivision on the reals is indeed is not normally considered closed. The implied closure properties you want are not customary.