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The refusal to do an ABI break is a crazy move on the C++ committee's part. C++ without an ABI break loses performance, has a bunch of confusing features (eg b
by pclmulqdq 4y ago
The refusal to do an ABI break is a crazy move on the C++ committee's part. C++ without an ABI break loses performance, has a bunch of confusing features (eg bucket iterators in hash tables...), and completely prevents a lot of proposals that would make smart pointers work a lot better.
- planede 4y agoNot entirely disagreeing there, but to clarify, breaking hash table iterator guarantees would be an API break, not merely an ABI break.