4 ms·
Especially if YCbCr is a linear transform of the RGB. (I'm not sure if it is, but it's likely to be close). If it is, it's essentially just making eigenvectors
by wiredfool 4y ago
Especially if YCbCr is a linear transform of the RGB. (I'm not sure if it is, but it's likely to be close). If it is, it's essentially just making eigenvectors from a matrix with a different set of bases.
- bob1029 4y ago> is a linear transform of the RGB It is for every implementation I've seen. I have it defined both ways as 4x4 matrices in my code (3x3 is not in System.Numerics).
- planede 4y agoIt appears to be a linear transform from "gamma-adjusted" RGB. So probably not straight from sRGB. [1] The article does not mention it, but I assume it just takes sRGB color components. [1] https://en.wikipedia.org/wiki/YCbCr#R'G'B'_to_Y'PbPr https://en.wikipedia.org/wiki/YCbCr#R'G'B'_to_Y'PbPr