4 ms·
For a finite circle, where you're on a line perpendicular to it going through its center, the gravitational force you experience towards it is exactly proportio
by penteract 4y ago
For a finite circle, where you're on a line perpendicular to it going through its center, the gravitational force you experience towards it is exactly proportional to the amount of your field of view it occupies - if I'm right, that should be proportional to `1-cos(atan(r/d))` where r is the radius of the circle and d is the distance between you and the center of the circle.